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If x, y, and z are positive numbers and 2x=3y=4z, then the value of x+y+z is how many times the value of x?
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tips?
First find the values of y and z in terms of x. Then insert them in x+y+z you will get \[\frac{ 13 }{ 6 }x\]This is to mean that x+y+z is 13/6 times grater than x.
wait a sec
x=1.5...
y=4/3
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hmm
Where you get this values?
wait
2x=3y
x=1.5, right?
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wait a sec
Nope x=1.5y
I got it!
6+4+3=13/6
I plugged in my own values
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I found a common least multiple
of x,y, and z
Then we done right?
yep
is that a final fantasy X boss you have there?
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