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Mathematics 13 Online
OpenStudy (anonymous):

Integration

OpenStudy (anonymous):

\[\int\limits_{?}^{?} \frac{ 1 }{ \sqrt{x}(1+x) }\]

OpenStudy (anonymous):

The question marks are not suppose to be there, so it's the problem without the question marks.

OpenStudy (experimentx):

\int just use like this for integration ... seems like trig subs seems to work also changing 1 + x = (1 + i sqrt(x))(1 - i sqrt(x)) and then taking partial fraction might work.

OpenStudy (anonymous):

i believe u-sub will work

OpenStudy (anonymous):

\[u=\sqrt{x}\] ha?

OpenStudy (experimentx):

woops!! that also works!!

OpenStudy (anonymous):

For this exercise, I'm technically not suposed to use partial fractions

OpenStudy (anonymous):

I may be missing something, but I can't seem to find the answer with u = \[\sqrt{x} \]

OpenStudy (experimentx):

change all x's into u's probably you would end up with 1/1+u^2 or something like that.

zepdrix (zepdrix):

You have to mess with the U a little bit kore :) but it will work.

hartnn (hartnn):

x= tan^2 theta might work

OpenStudy (experimentx):

this is same as using trig subs x = tan^2 theta in original.

OpenStudy (experimentx):

but lol ... we know int 1/1+x^2 = arctan (x) which is one of the standard integral.

OpenStudy (anonymous):

I got it! Yes!!! I was substituting the first \[\sqrt{x} \] in the integrand. Then, I realized that it gets canceled out. Thank you very much everyone! ... If it wasn't for you, I probably would have spent another 10 minutes on this. -.-

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