Question

when heated, KCIO3 decomposes into KCI and o2. If this reaction produced 14.5 grams of KCI, how much O2 was produced (in grams)?

Answer 1

ok so first write ballanced chemical equation and then we will go on...

Answer 2

2 KClO3 -> 2 KCl + 3 O2
so you dont know basics... lets move further on:
we write down what we have and what we want:
m(KCl) = 14,5 g
---------------
m(O2) = ?

now when you learn this routine in solving this kind of problems you wont have any more problems just follow these steps:
n(O2)/n(KCl) = 3/2
n(O2) = 3/2 n(KCl)
n(O2) = 3/2 * m(KCl)/M(KCl)

now since n=m/M
m(O2) = 3/2 * [m(KCl)/M(KCl)] * M(O2)

any questions?

Answer 3

can someone explain more. I still don't get it.