Question

d/dt (1-tan t/sec t)

Answer 1

you can re-write as
\[1- \frac{ \sin(t) \cos(t) }{ \cos(t) }\]

Answer 2

aka
the derivative of -sin(t)

Answer 3

what about 1/(1/cos)?

Answer 4

=cos

Answer 5

shouldn't is be cos-sin?

Answer 6

*it

Answer 7

why? because the problem is actually
\[\frac{ d}{dt }\frac{ 1-\tan t }{\sec t }\]
?

Answer 8

i get it now, sorry about that! thanks again