probability Jeanie is a bit forgetful, and if she doesn't make a "to do" list, the probability that she forgets something she is supposed to do is .2. Tomorrow she intends to run three errands, and she fails to write them on her list . What is the probability that Jeanie remembers the first errand but not the second or third?
4 out of 5 options fulfill this condition for the 1st item of those 4, 1/5 fulfill the second and of the remaining 1/5 fulfill the third. so your answer is found by multiplying (4/5)(1/5)(1/5)
0.8 * 0.2* 0.2 =4/125
then viktor.ray isnt right either so dont try that either
sorry, everything is all right
:)
o.O phew
thank you both)
it is like if she remember first that means this probability would be 0.8 (1-0.2=0.8), so i need multiply 08*0.2*0.2
yes exactly
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