Question

Algebra II question, a fraction on top of a fraction, please help me!

Answer 1

a fraction on top of a fraction can be rewritten as say (2/3)/(3/4) then you can flip the second one because to divide you multiply by the reciprocal (2/3)*(4/3) then you multiply across the fractions (2*4)/(3*3).

Answer 2

\[\huge\frac{\frac{30x^2+27x+6}{9x^2-49}}{\frac{30x+15}{30x-70}}\] That is the fraction.

Answer 3

@cpattison

Answer 4

@ganeshie8 @Hero

Answer 5

oh okay

Answer 6

one second!

Answer 7

Put a divide sign between both of them, then put them next to each other. You'll know what to do then.

Answer 8

\[\huge\frac{30x^2+27x+6}{9x^2-49} \div \frac{30x+15}{30x-70} \]

Answer 9

((30x2+27x+6)/(9x2−49))/((30x+15)/(30x−70)) is where we start.
then you can flip the bottom half and multiply ((30x2+27x+6)/(9x2−49))*((30x−70)/(30x+15)) then you just multiply though ((30x2+27x+6)*(30x−70))/((9x2−49)*(30x+15))

Answer 10

yeah so flip that second fraction

Answer 11

i really have to learn how to use the equation bar

Answer 12

@cpattison you should use the \\[LaTeX\] by using the \[\\] minus the \ in the middle.

Answer 13

agreed

Answer 14

I just copied and pasted what @andriod09 wrote with a few minor changes :P

Answer 15

\[\huge\text i-know-how-to-use-LaTeX\]

Answer 16

Not as good as me :P

Answer 17

the answer isn't supposed to be like that. it is supposed to be on top of each other though. thats what it says. the answer it:
\[\frac{2(5x+2)}{(x-7)}\]

Answer 18

You failed to execute the proper steps. That's why you didn't get it right

Answer 19

Did you flip the second fraction?

Answer 20

no. i don't know how to solve it like that, you have to factor it out is what the book says, but i don't get it.

Answer 21

If you had \[\frac{3}{6} \div \frac{3}{9}\] you would have no clue what to do?

Answer 22

thats simple:
\[\frac{3}{6}\div\frac{3}{9}=\frac{1.5}{1}\]

Answer 23

\[:{\]

Answer 24

actually, you have it but you failed to execuate the reciprocal rule

Answer 25

\[:[\]

Answer 26

\[\frac{3}{6}\div\frac{3}{9}=\frac{3}{6} \times \frac{9}{3} = \frac{3}{2}\]

Answer 27

But really, you're supposed to do the reciprocal then reduce in this manner:

\[\frac{3}{6}\div\frac{3}{9}=\frac{3}{6} \times \frac{9}{3} =\frac{1}{2} \times 3= \frac{3}{2}\]

Answer 28

Show me the full steps of how you got 1.5 from 3/6 div 3/9 @andriod09

Answer 29

You must have used a calculator bro, lol

Answer 30

Because you never divide by fractions to get a decimal. Only a calculator would do that.

Answer 31

\[\frac{3}{6}\div\frac{3}{9}=\frac{3}{6}\times\frac{9}{3}=\frac{1}{2}\times3=\frac{3}{2}\]

Answer 32

btw, hero i literally typed all that out.

Answer 33

Good for you. Now do your original problem in the same manner.