A solution of 78% alcohol is to be mixed with a solution of 23% alcohol to form 165 L of a 58% solution. How many liters of the 78% solution must be used?

Question

anonymous · Answer

lets put the number of L  of 78% alcohol as $x$ so the number of L of 23% solution must be $165-x$ since the total L is 165

anonymous · Answer

then you will have 
$.78x+.23(165-x)$ liters of alcohol, which you want to be equal to $.58\times 165=95.7$

anonymous · Answer

so set 
$$.78x+.23(165-x)=95.7$$ and solve for $x$ although it is easier to multiply both sides by 100 and solve 
$$78x+23(165-x)=9570$$

anonymous · Answer

you just confuse me dude

anonymous · Answer

all steps are there and explained in the best english i know how. 
since you will probably have to do more of these, it might be a good idea to follow the steps and see if you understand them. 

perhaps there is a better (clearer) explanation in your text

anonymous · Answer

105 is what i got?

anonymous · Answer

or is it 57.178?

anonymous · Answer

help  me please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!