Question

limit

Answer 1

\[\lim_{x \rightarrow 9}\frac{ x-9 }{ \sqrt{x}-3 }\]

Answer 2

Multiply top and bottom by the conjugate of the denominator. You should then be able to cancel and find the limit.

Answer 3

ohhh thank you @dylanhouse :)

Answer 4

or try factoring the numerator as
\[(\sqrt{x}+3)(\sqrt{x}-3)\]and then cancelling

Answer 5

Oh yeah both would work right ?

Answer 6

yes

Answer 7

you will get \(\sqrt{x}+3\) not matter what
then replace \(x\) by 9

Answer 8

\[\frac{ x-9 }{\sqrt{x}-3 } \times \frac{ \sqrt{x}+3 }{ \sqrt{x}+3 }\]

Answer 9

Now just expand.

Answer 10

=6

Answer 11

Absolutely :)