Question

find the slope of the line tangent to the following curve where x = 1...

Answer 1

\[y = \sin[x - \tan (\frac{ \Pi }{ 4 }x^{66})] + x ^{\frac{ 1 }{ 1 + 66\Pi }}\]

Answer 2

if you cant see the exponent part at the end, its:
\[\frac{ 1 }{ 1+66\Pi }\]

Answer 3

answer is -99Pi

Answer 4

im currently at this step:
\[\frac{ -66\Pi }{ 4} + \frac{ 1 }{ 1 + 66\Pi }\]

Answer 5

Oh goodness.. this one again iop? XD

Answer 6

heh

Answer 7

Hmm

Answer 8

What is that symbol? Is that suppose to be pi?

Answer 9

yes

Answer 10

Why don't u use lowercase? D: that's so confusing..

Answer 11

i was wondering if that was confusing people

Answer 12

i guess so

Answer 13

Hmm you sure the step you got to is correct so far? :O

Answer 14

i got this for y prime:
\[y' = \cos[x - \tan(\frac{ \pi }{ 4 }x^{66})](1 - \sec^2(\frac{ \pi }{ 4 }x^{66}))(\frac{ 66\pi }{ 4 }x^{65}) + \frac{ 1 }{ 1+66\pi }x^\frac{ 1 }{ 1+66\pi }-1\]

Answer 15

So what i tried to do is...
After you get a common denominator and all that jazz.. you have something that looks like a polynomial in the numerator.

And I'm not seeing it factor nicely :( at least not in any way that will cancel with the denominator. Hmmm

Answer 16

plugged 1 in..
\[y'(1) = 1(-1)(\frac{ 66\pi }{ 4 })(\frac{ 1 }{ 1+ 66\pi })\]

Answer 17

lol

Answer 18

the factoring is the confusing part... how am i supposed to get it to -99pi

Answer 19

unless the steps i did to get it to that point were incorrect...i dont think so

Answer 20

Hmm yah your steps look good so far :o