Question

An object is thrown upward from the top of a 192-foot building with an initial velocity of 16 feet per second. The height of the object after the t seconds is given by -16t^2+16+192. Factor this polynomial.

Answer 1

Use the quadratic equation :)

Answer 2

I don't know what that is

Answer 3

they want the answer to look like this............ -16t(t- )(t+ )

Answer 4

I assume that should be +16t and not just +16?

Answer 5

no part of the answer is -16.

Answer 6

well, you take out the common factor of -16. So you get: -16(t^2 -t-12). Then factor the inside brackets as: -16(t-4)(t+3)

Answer 7

I have already tried that answer and it's not the right answer

Answer 8

If you are only asked to factor, that is definitely the correct answer if the equation is: -16t^2 + 16t +192.

Answer 9

this is the question.............. An object is thrown upward from the top of a 192-foot building with an initial velocity of 16 feet per second. The height of the object after the t seconds is given by -16t^2+16+192. Factor this polynomial.

Answer 10

If that is the question, assuming there is a t after that second 16 in the equation,my answer I gave is correct. The form of the answer they gave you is impossible as it would produce an x^3 which is not in the equation.

Answer 11

I have put the answer -16t(t-4)(t+3) in and I get the following message..... Sorry that is not correct........ First factor out the greatest common factor ( if there is one other than 1 or -1) then factor the remaining trinomial

Answer 12

I'm not sure then. We did exactly as they said. Factored out the -16 and then factored the remaining trinomial to (t-4)(t+3).

Answer 13

this is like the third time you've posted this problem.

Answer 14

Assuming you have copied correctly:
\[-16t ^{2}+16+192\]\[-16t ^{2}+208=208-16t ^{2}\]\[16(13-t ^{2})\]