Question

how do I find all the zeroes of the equation x^3-x^2=3x+3

Answer 1

yes it's x

Answer 2

Set the equation equal to zero by bringing the 3x and 3 to the left.

Answer 3

this is the original problem, yes set = to 0

Answer 4

i just typed in original equation

Answer 5

you sure thats +3 and not -3 on RHS..

Answer 6

yes

Answer 7

choices are i sq rt3, -i sq rt 3, -1 or i sq rt 3, -i sq rt 3, 1 or sq rt 3, -sq rt 3, -1

Answer 8

You can substitute in:
\[y = -x\]

Answer 9

then factor in terms of y

Answer 10

aahh,,i see now..
go for sum of roots,product in pairs, and product of roots thing then ..

Answer 11

then convert back to x

Answer 12

agh! sorry, misread equation.

Answer 13

k

Answer 14

the original question is perfectly fine. The "zero" of an equation is the same a "root" of the equation. you don't need a y. So the sign IS different? Thats makes a huge difference because then it factors easily. Otherwise its a serious problem