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Mathematics 16 Online
OpenStudy (anonymous):

limits

OpenStudy (anonymous):

OpenStudy (anonymous):

\[\lim_{x \rightarrow -3} f(x) = \] 1 ?

OpenStudy (anonymous):

@hartnn can you just check my work, i attempted all of the problems

OpenStudy (anonymous):

\[f(-3)\]

OpenStudy (anonymous):

f(-1)=1

OpenStudy (anonymous):

\[\lim_{x \rightarrow -1} f(x) =2\]

OpenStudy (anonymous):

first limit is incorrect

hartnn (hartnn):

lim x-> -1 f(x) = f(-1) = 1 hmmm, why @completeidiot ?

OpenStudy (anonymous):

lim x->-3 for f(x) is not 1

OpenStudy (anonymous):

if you take the limit from the right, you get 1 if you take the limit from the left, you get 2 1 is not equal to 2 thus no limit correct me if i am wrong

OpenStudy (anonymous):

so limit wouldn't exist ?

hartnn (hartnn):

isn't that filled circle mean its already defined and given to be '1'

OpenStudy (anonymous):

f(-3)=? --incomplete f(-1)=1 -- correct lim x->-1 f(x) = 2 -- correct

OpenStudy (anonymous):

f(-3) would be equal to 1 but lim x->-3 f(x) is not the same as f(-3)

OpenStudy (anonymous):

f(-3)=1

OpenStudy (anonymous):

oh so that would be undefined ?

OpenStudy (anonymous):

its convient to just plug in numbers, but you need to remember that limits means, "approaches" not is equal to yes it would be undefined

OpenStudy (anonymous):

5. f(1)= 1

OpenStudy (anonymous):

im going to assume so, cause there's a giant hazy blob around (1,1)

OpenStudy (anonymous):

6. \[\lim_{x \rightarrow 1} f(x) = \]

OpenStudy (anonymous):

1

OpenStudy (anonymous):

cant say for sure, i would assume so

OpenStudy (anonymous):

7. \[\lim_{x \rightarrow 1^{-}} f(x)=1\]

OpenStudy (anonymous):

lim_{x rightarrow 1^{+}} f(x)=1

OpenStudy (anonymous):

\[\lim_{x \rightarrow 1^{+}} f(x)=1 \]

OpenStudy (anonymous):

im not sure about the last two :S

OpenStudy (anonymous):

from the left is definitely 1, but from the right, i cant tell cause it just looks like a giant blob

OpenStudy (anonymous):

there's a full dot on the blob too

OpenStudy (anonymous):

i would say there's no limit from the right because its oscillating infinitely fast

OpenStudy (anonymous):

or undefined for lim x→1^+ f(x) that being said, then lim x->1 f(x) would also be undefined sorry cant help you there, use your best judgement

OpenStudy (anonymous):

hmm okay, thank you anyways :D

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