limits
\[\lim_{x \rightarrow -3} f(x) = \] 1 ?
@hartnn can you just check my work, i attempted all of the problems
\[f(-3)\]
f(-1)=1
\[\lim_{x \rightarrow -1} f(x) =2\]
first limit is incorrect
lim x-> -1 f(x) = f(-1) = 1 hmmm, why @completeidiot ?
lim x->-3 for f(x) is not 1
if you take the limit from the right, you get 1 if you take the limit from the left, you get 2 1 is not equal to 2 thus no limit correct me if i am wrong
so limit wouldn't exist ?
isn't that filled circle mean its already defined and given to be '1'
f(-3)=? --incomplete f(-1)=1 -- correct lim x->-1 f(x) = 2 -- correct
f(-3) would be equal to 1 but lim x->-3 f(x) is not the same as f(-3)
f(-3)=1
oh so that would be undefined ?
its convient to just plug in numbers, but you need to remember that limits means, "approaches" not is equal to yes it would be undefined
5. f(1)= 1
im going to assume so, cause there's a giant hazy blob around (1,1)
6. \[\lim_{x \rightarrow 1} f(x) = \]
1
cant say for sure, i would assume so
7. \[\lim_{x \rightarrow 1^{-}} f(x)=1\]
lim_{x rightarrow 1^{+}} f(x)=1
\[\lim_{x \rightarrow 1^{+}} f(x)=1 \]
im not sure about the last two :S
from the left is definitely 1, but from the right, i cant tell cause it just looks like a giant blob
there's a full dot on the blob too
i would say there's no limit from the right because its oscillating infinitely fast
or undefined for lim x→1^+ f(x) that being said, then lim x->1 f(x) would also be undefined sorry cant help you there, use your best judgement
hmm okay, thank you anyways :D
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