Question

Solve the equations:
x^2+y^2=169,
x-y-13=0.
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ANSWER = {(13,0),(0,-13)}

Answer 1

x = y + 13

Answer 2

\[(y + 13)^2 = y^2 + 26y +169\]

Answer 3

write x^2+y^2 = (x-y)^2 +2xy

Answer 4

so:
\[2y^2 + 26 +169 = 169\]

Answer 5

\[2y(y+13) = 0\]

Answer 6

forgot a y two posts up

Answer 7

y = 0, or 13

Answer 8

the rest is trivial

Answer 9

negative 13

Answer 10

typos :(

Answer 11

how did 2y(y+13)=0

Answer 12

you cancel 169, and factor out a 2y

Answer 13

i am not gettin it

Answer 14

2y^2+26+169=169 HOW!!!!!

Answer 15

\[(y+13)^2 + y^2 = 169\]
\[(y^2 + 26y + 169) + y^2 = 169\]
\[2y^2 + 26 + 169 = 169\]

Answer 16

what about the values of x? how will i get those

Answer 17

then you just use the second equation

Answer 18

if y = 0:
\[x-(0)-13 = 0\]

Answer 19

then x = 13

Answer 20

exactly

Answer 21

so the ordered pair is (13,0)

Answer 22

ok done@ pretty easy method of solving thanks

Answer 23

Yeah that's right @MrMoose It's correct

Answer 24

You are welcome