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Solve the equation (eqn coming soon) . . ANSWER = {-1,5 pm 2 sqrt6
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\[(x-\frac{ 1 }{ x })^2-8(x+\frac{ 1 }{x })-16=0\]
i have solved this and i am getting 2 values of y
\[y=4+4\sqrt{2}, y=4-4\sqrt{2}\]
have u written (x-1/x)^2 as (x+1/x)^2 -4 ? and then put y= x+1/x
yes i have done it all
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then u should get y =10 or -2
i asked a question like this hours ago right
yes. and i have helped u solve..... why u not getting y = 10,-2 ??
y^2-8y-16=0 this is the quadratic
\(\huge (x-1/x)^2 as (x+1/x)^2 -4\)
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u forgot -4
y^2-8y-20=0 is'nt it
yes. y=?
y=10 and y=-2
yesm now put y=x+1/x
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10=x+1/x right?
yes, solve that quadratic.....
done
\[x=5\pm 4\sqrt{6} and x=-1\]
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