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Mathematics 9 Online
OpenStudy (anonymous):

Determine whether the vectors u and v are parallel, orthogonal, or neither. u = <10, 6>, v = <9, 5>

OpenStudy (anonymous):

Orthogonal Parallel Neither

OpenStudy (anonymous):

@TuringTest

OpenStudy (turingtest):

the dot product determines the relative orientation of two vectors\[\vec u\cdot\vec v=\|\vec u\|\|\vec v\|\cos\theta_{uv}\]

OpenStudy (turingtest):

theta is the angle between u and v. when two vectors are parallel, the angle between them is zero, and the formula reduces to\[\vec u\cdot\vec v=\|\vec u\|\|\vec v\|\]so if the dot product of two vectors is euqla to the product of their magnitudes, they are parallel

OpenStudy (turingtest):

equal*

OpenStudy (turingtest):

similarly, if they are orthogonal the angle between them is pi/2, the cosine of which is zero, so the formula reduces to\[\vec u\cdot\vec v=0\]hence if the dot product between them is zero then they are orthogonal

OpenStudy (turingtest):

if neither of the above is true then they are neither parallel nor orthogonal

OpenStudy (anonymous):

so in this case?

OpenStudy (turingtest):

what do you get when you do the dot product?

OpenStudy (anonymous):

how do i do that? im not well at math?

OpenStudy (anonymous):

@TuringTest

OpenStudy (turingtest):

me thinks you have been skipping lessons...\[\vec u=\langle a_1,b_1\rangle\]\[\vec v=\langle a_2,b_2\rangle\]\[\vec u\cdot\vec v=a_1a_2+b_1b_2\]

OpenStudy (anonymous):

take the dot product - if its zero, then they are orthogonal if not, see if one is a multiple of the other - if so they are parallel if not, neither

OpenStudy (turingtest):

yes, that is a faster way to check that they are parallel, goo point @gregohb

OpenStudy (turingtest):

good*

OpenStudy (anonymous):

but how do i take the dot product??

OpenStudy (turingtest):

read 4 posts up, I wrote the formula

OpenStudy (turingtest):

multiply each respective component and add the results

OpenStudy (anonymous):

|dw:1349621897381:dw||dw:1349621971407:dw||dw:1349622040744:dw|

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