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Mathematics 18 Online
OpenStudy (anonymous):

Solve this system of equation using the linear combinations method. 2x - 4y = 4 -3x + 10y = 14

OpenStudy (anonymous):

[2x-4y=4] * -3 [-3x+10y=14] *2 -6x+12y=-12 -6x+20y=28 ______________ 0x-8y=-40 y= -40/-8 y= 5 2x-4(5)=4 2x-20=4 2x=24 x=12 This method is known as elimination

OpenStudy (anonymous):

Thanks so much but , may I ask .. Why did you multiply by -3 ?

OpenStudy (anonymous):

The goal of the elimination method is to eliminate a variable in order to solve for another variable. In this case I chose to eliminate x and solve for y. In order to eliminate x, you can multiply your first equation by the x value in your second equation (-3), and multiply your second equation by the x value in your first equation (2). Now the x values in both of you equations are -6, and you can subtract -6 - (-6) = 0 in order to eliminate x and solve for y.

OpenStudy (anonymous):

Would you do the same if you were eliminating y and solving for x?

OpenStudy (anonymous):

Exactly. Try eliminating y and solving for x

OpenStudy (anonymous):

so if I was eliminating y , would I have to multiply the first equation by +4 and the second equation by -10 ?

OpenStudy (anonymous):

Other way around. You would multiply the first equation by 10 and the second equation by -4. Remember that your goal is to get the y values in both of your equations equal to each other

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