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Mathematics 16 Online
OpenStudy (anonymous):

limit

OpenStudy (anonymous):

prove that \[\lim_{x \rightarrow a} f(x)\] =L

OpenStudy (anonymous):

if and only if \[\lim_{x \rightarrow a} (f(x)-L)\]

OpenStudy (anonymous):

does: \[\lim_{x \rightarrow a}(f(x)-L) = 0\] ?

OpenStudy (anonymous):

if so: \[\lim_{x \rightarrow a}(f(x)-L)=\lim_{x \rightarrow a}f(x) + \lim_{x \rightarrow a}(L)\]

OpenStudy (anonymous):

by linearity

OpenStudy (anonymous):

the second term is just L \[\lim_{x \rightarrow a}f(x) - L = 0\]

OpenStudy (anonymous):

Sorry, three posts up I made a typo, should be limf(x) - lim(L)

OpenStudy (anonymous):

anyway, then through algebra, you get: \[\lim_{x \rightarrow a}f(x) = L\]

OpenStudy (anonymous):

okk

OpenStudy (anonymous):

here are some limit properties: http://tutorial.math.lamar.edu/Classes/CalcI/LimitsProperties.aspx

OpenStudy (anonymous):

what about \[\lim_{x \rightarrow a} |f(x)| =|L|\]

OpenStudy (anonymous):

then you have: \[\pm \lim_{x \rightarrow a}f(x) = \pm L\]

OpenStudy (anonymous):

Out of that, you get two cases: \[\lim_{x \rightarrow a}f(x) =L\] and \[\lim_{x \rightarrow a}f(x) =-L\]

OpenStudy (anonymous):

how to prove left hand side is equal right hand side

OpenStudy (anonymous):

list out the four cases

OpenStudy (anonymous):

\[\lim_{x \rightarrow a}f(x) = L\] \[\lim_{x \rightarrow a}f(x) = -L\] \[-\lim_{x \rightarrow a}f(x) = L\] \[-\lim_{x \rightarrow a}f(x) = -L\]

OpenStudy (anonymous):

the negatives cancel in the last one

OpenStudy (anonymous):

and you can just divide by -1 in the second one

OpenStudy (anonymous):

my question is prove that \[\lim_{x \rightarrow a} |f(x)| = |L|\] if and only if \[\lim_{x \rightarrow a}( f(x)-L)\]

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