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Mathematics 26 Online
OpenStudy (anonymous):

Let k(x) = x^5 + 3x -2 and let k^-1 denote the inverse of k. Then, find (k^-1)'(2)

OpenStudy (anonymous):

actually in such cases u dont need to find the inverse itself and differentiate it... so what is the formula for the derivative of inverse?

OpenStudy (anonymous):

\[(f^{-1}(x))'=\frac{1}{f'(f^{-1}(x))}\]am i right ?

OpenStudy (anonymous):

yes...

OpenStudy (anonymous):

how about the asker? are u familiar with that formula?

OpenStudy (anonymous):

ok i gotta go but here are some hints for u MrOrbit\[(f^{-1})'(2)=\frac{1}{f'(f^{-1}(2))}\]so all that u need is finding\[f^{-1}(2)\]for reaching there note that\[f(1)=2\]

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