Find the absolute maximum and minimum values of f on the set D.
f(x,y) = x^2+y^2+(x^2)y+4
D = abs(x)

Question

Find the absolute maximum and minimum values of f on the set D. 
f(x,y) = x^2+y^2+(x^2)y+4
D = abs(x)<or=1, abs(y)<or=1

anonymous · Answer

$$f(x,y)=x^2+y^2+x^2y+4 $$
$$D=\left| x \right|\le 1, \left| y \right|\le 1$$

anonymous · Answer

ok u have a continous function so u just need to find extremums in given region ; setting partial derivatives equal to zero$$\frac{\partial f}{\partial x}=0$$$$\frac{\partial f}{\partial y}=0$$and finally compare the values of extremums with value of function at boudaries

anonymous · Answer

when u want to find max and min at boundaries for example this one|dw:1349636466076:dw|