find the absolute value of the difference of the solutions to the equation 3^2x -10(3^x) +9=0.
let u=3^x
@TuringTest then what would the equation be? and what would you do next?
if u=3^x what is u^2=?
@TuringTest would it be 3^2x?
yep :) so now make the substitutions into the equation and you will get a regular quadratic
@TuringTest the the equation would be U^2-10U+9 and then you factor? i have no clue!
what two numbers multiply to make 9 and add to make -10 ?
@TuringTest i know how to factor and i got (u-9)(u-1) then what
the zero factor property states that\[(u-9)(u-1)=0\]implies that either\[u-9=0~~~~or~~~~u-1=0\]or both solve those two equations separately, then sub back in for u
@TuringTest can you show me how to do that im confused
can you solve u-9=0 for u ? I sure hope so
yes so you put those answers back in to the equation for X then what @TuringTest
what do you mean "put them in the equation for x" ? We are solving for u, not x yet what are the two solutions for u ?
9 and 1 @TuringTest
yes, so we have u=1 and u=9 now sub back in our original expression for u and what do we get?
would the equations then be 3^18 -10(3^9)+9 and 3^2 -10(3) +9 @TuringTest
you plugged in the values for u into where the x goes, that's not right. all I'm asking you to do is put the expressions u=1 and u=9 back in terms of x
you also don't need to write @turingtest every time...
they want to absolute value of the difference of the two solutions we have the two solutions in terms of u undo our original sub for u to find what x is supposed to be
9=3^x 1=3^x?
yes, excellent can you solve those for x?
x=2,0
great, and the absolute value of the difference of those two solutions is...?
2
which is your answer, nice job :)
thanks so much!:)
very welcome!
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