Question

factor
2x^2+11x+12

3x^4-12

9x^2-25y^2

Answer 1

You want to find your x and y values, correct?

Answer 2

for the 3rd problem

Answer 3

no i need to factor

Answer 4

So we are looking for something like (?X + ?Y)(?X + ?Y)

Answer 5

yes

Answer 6

What are the factors of 9 you could use
and what are the factors of 25 you could use?

Answer 7

when you have a quad equation of the form \[ax ^{2}+bx+c\], the factors of a*c must add up to b

Answer 8

For 9 the only factors you have are 1, 3, 9. For 25 you have 1, 5, 25, correct?

Answer 9

ok

Answer 10

So you want to multiply two numbers (1,3,9) to get 9 and two (1,5,25) to get 25 but will cancel out when you add them together.

(3x + 5y) and ?

Answer 11

(3x-5y)

Answer 12

correct!

Answer 13

what about the first problem

Answer 14

So when you factor it out you get \[9x ^{2} + 15xy - 15xy - 25y ^{2}\]

Answer 15

So we are looking for (2X + ?) (X + ?) where the ?'s have to equal 12 when we multiply them and helps make 11x for the middle. There are two ways you can do this. First what I call PP (Plug and Pray) or the Quadratic Formula (Have you learned this one yet)?

Answer 16

(2x+3)(x+4)

Answer 17

There ya go!

Answer 18

ok great thxs

Answer 19

np