Let w be a vector in the vector space V. Show that the sets of vectors {w, 0} and {w, -w} are linearly dependent.
Just take the determinant of the matrix formed with those vectors as columns. If it's non-zero the set is linearly independent
But it doesn't say how many entries each vector has or anything, it just says a vector w of anysize.
you mean the vectors are not\[\langle w,0\rangle\]and\[\langle w,-w\rangle\]?
that represents something else?
i take it as \[w=\left(\begin{matrix} a _{1}\\ ..\\a _{n}\ \end{matrix}\right)\] and the first is the set of the two vectors w and the 0 vectors, and the next is the set w and -w... not as w being a single value entry
That really doesn't make a lot of sense to me, I must say. I don't see much logic in saying that the set\[\{\vec w,\vec 0\}\]is linearly independent. I could be completely misreading the question though...
I also don't understand what it means to compare the two sets like that if that';s what they want.
Can I just say... if A={w,0}, and then since Ax=0 that not just the trivial solution exists for (x,y), and y can be any value, that the systems is dependent. I believe they are saying, show that the two vectors w, and the zero vector are dependent... and also show that the two vectors w and -w are dependent... showing two separate cases.
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