Question

factor

8m^3+m^6-20
-37x^2+x^4+36
ac+cd-ab-bd
m^6-1
a^8-b^8

Answer 1

Which do you want to start with?

Answer 2

the first

Answer 3

Best to rearrange it from highest exponent to lowest.
\[m ^{6}+8m ^{3}-20\]

Answer 4

So we are looking for (m^? + ?) (m^? - ?). So we need to do one of two things. First what I call PP (Plug and Play) or second the Quadratic Formula.

Answer 5

y would we do the Q formula if its m^6 and m^3

Answer 6

You don't worry about the exponents just the values before the x's so 1,8,-20

Answer 7

ok

Answer 8

Are you comfortable with the quad or want to PP?

Answer 9

im comfortable with the quad

Answer 10

ok so its (m^3+2)(m^3-10)

Answer 11

\[\frac{ -8 +/- \sqrt{(8)^{2}} -4(1)(20) }{ 2(1) }\]

Answer 12

Close, that would give you \[m^{6} + 2m ^{3}-10m ^{3}-20\], correct?

Answer 13

so you would have a -8m^3

Answer 14

ok then (m^3-2)(m^3+10)

Answer 15

yes.

Answer 16

ok next one

Answer 17

Work it out the same way you did the first one.

Answer 18

srry third one i mean the second one is (-x^2-36)(X^2-1)

Answer 19

Close on the second one, might want to check your signs.

Answer 20

For the third one you will want to seperate them right away into ( ) ( ) and then see if you can find a commonality in the ( ). Did this make sense?

Answer 21

NOPE

Answer 22

take (ac+cd) - (ab - bd)

Answer 23

do you see an (a+d) in both ( )'s

Answer 24

Hint: Factor something out.

Answer 25

BRB

Answer 26

i see an a- d and an a-d

Answer 27

a+d i mean

Answer 28

Sorry, little ones woke up.
So did you get c(a+d) - (-b)(a+d)?

Then you have (c+b)(a+d).

Answer 29

I am going to have to go.
Hint #4 (Perfect square) (?+?)(?-?)
Hint #5 ( Same as #4).

Hope I helped some.

Sorry I had to go.