Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

derivative of x^sqrtx?

OpenStudy (anonymous):

so we are finding the derivative of: \[x*\sqrt{x}\]

zepdrix (zepdrix):

Are you familiar with logarithmic differentiation ethayer? :)

OpenStudy (turingtest):

\[\large x^{\sqrt x}\]

OpenStudy (anonymous):

ah

OpenStudy (anonymous):

zepdrix, is that taking the natural log of both sides?

zepdrix (zepdrix):

Yes, it will allow us to get the variable OUT of the exponent (using properties of logs)! :) Making the problem doable (with the product rule).

OpenStudy (anonymous):

TuringTest please explain it.

OpenStudy (turingtest):

@zepdrix seems to have a handle on it

OpenStudy (turingtest):

\[\large y=x^{\sqrt x}\]take the natural log of both sides

zepdrix (zepdrix):

Just post a response if you get stuck ethayer. Try to remember your rules of logs, how you can move that exponent OUT of the log! :D

OpenStudy (anonymous):

lny = sqrtx * lnx?

OpenStudy (turingtest):

now differentiate implicitly

OpenStudy (anonymous):

what does that exactly mean? take both sides to the power of e?

OpenStudy (turingtest):

no, take the derivative on both sides with respect to x

OpenStudy (turingtest):

for \(\frac d{dx}\ln y\) you will need the chain rule

OpenStudy (anonymous):

dy/y = [1/2sqrt(x)*ln(x)] + [sqrtx * 1/x]?

OpenStudy (turingtest):

it's better to write y', not dy (dy is a differential, which is a different thing) but aside from that, yes

OpenStudy (anonymous):

then i just multiply by the original y?

OpenStudy (turingtest):

yes

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!