derivative of x^sqrtx?
so we are finding the derivative of: \[x*\sqrt{x}\]
Are you familiar with logarithmic differentiation ethayer? :)
\[\large x^{\sqrt x}\]
ah
zepdrix, is that taking the natural log of both sides?
Yes, it will allow us to get the variable OUT of the exponent (using properties of logs)! :) Making the problem doable (with the product rule).
TuringTest please explain it.
@zepdrix seems to have a handle on it
\[\large y=x^{\sqrt x}\]take the natural log of both sides
Just post a response if you get stuck ethayer. Try to remember your rules of logs, how you can move that exponent OUT of the log! :D
lny = sqrtx * lnx?
now differentiate implicitly
what does that exactly mean? take both sides to the power of e?
no, take the derivative on both sides with respect to x
for \(\frac d{dx}\ln y\) you will need the chain rule
dy/y = [1/2sqrt(x)*ln(x)] + [sqrtx * 1/x]?
it's better to write y', not dy (dy is a differential, which is a different thing) but aside from that, yes
then i just multiply by the original y?
yes
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