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Mathematics 7 Online
OpenStudy (anonymous):

simplify. state restrictions. 7x/x+4 + 3x/x-6

OpenStudy (anonymous):

well, the denominator cannot be 0

OpenStudy (anonymous):

how would I simplify though

OpenStudy (anonymous):

im going to assume that your question is simplify \[\frac{7x}{x+4}+\frac{3x}{x-6}\] well in order to add fractions together, they need to have the same denominator so you first need to determine what lcd or gcm or gcd or whatever its called once you figure that out, you need to determine what you must multiply to each fraction seperately so they then have the same denominator,

OpenStudy (anonymous):

yes I just needed help to determine the LCD. Wouldn't it be x^2-12 ?

OpenStudy (anonymous):

how did you get that?

OpenStudy (anonymous):

well the lcd for 4 and 6 is 12

OpenStudy (anonymous):

or would it be 12x-12? :S im not sure

OpenStudy (anonymous):

yes normally that is true, but in your case, you're not just dealing with 4 and 6 you're dealing with (x+4) and (x-6)

OpenStudy (anonymous):

oh okay, so how would I determine the lcd

OpenStudy (anonymous):

well you dont really need to determine lcd, you just want the 2 fractions to have common denominator the simpliest way would jsut be to multiply the 2 denominators together so the denonminator would be (x+4)*(x-6) if you want to expand that, go for it, but you can just leave it as is once you determine that the denominator will be (x+4)(x-6) you need to multiply each fraction by something so they will be fractions with that denominator

OpenStudy (anonymous):

okay thank you so much, I understand now

OpenStudy (anonymous):

just to make sure, for the first fraction, you would have to multiply it by (x-6)/(x-6) so what would you need to multiply to the 2nd fraction?

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