Question

Find the larger of two consecutive integers whose sum is 4 less than three times the smaller integer. how would I be to set up this problem.

Answer 1

so:
\[x + (x-1) = 3(x-1) - 4\]

Answer 2

where x is the larger integer and x-1 is the smaller integer

Answer 3

ok thanks ill tell you my anwser after i work it out will you tell me if i am correct?

Answer 4

ok

Answer 5

is the second step 1x-1= 3x-3-4?

Answer 6

the Left Hand Side is incorrect, look at your x's

Answer 7

2x-1=3x-3-4

Answer 8

Yes

Answer 9

how would i get to the 3rd step because it is a werid looking problem to me haha

Answer 10

first combine terms on the right hand side

Answer 11

is it 2x-1=3x-7?

Answer 12

yes

Answer 13

now get all of the x's on one side and all of the constants on the other

Answer 14

5x=-6 or am i totally wrong?

Answer 15

Be careful with your signs

Answer 16

is is 2x-3x

Answer 17

1x=-6?

Answer 18

close!

Answer 19

-1x=-6?

Answer 20

yes, so
x= ?

Answer 21

-6

Answer 22

\[-x = -6\]
divide by -1 on both sides:
\[x = 6\]

Answer 23

when ever you divide by to negitives you get a positive i forgot that thanks :) so do i do 6-1for the seccond number ?

Answer 24

yes

Answer 25

so it would be 5,6?

Answer 26

yes

Answer 27

thanks you so much i really apricaite you taking your time to help me :)

Answer 28

You are welcome