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Mathematics 16 Online
OpenStudy (anonymous):

How to graph x is less than or equal to 0. And the inequality shading thing.

OpenStudy (anonymous):

There would be a straight line of x=0, not dotted since it's inclusive...and shade the whole graph under that line...so quadrants 2 and 3 would be shaded in with a solid line at x=0

OpenStudy (anonymous):

I get y > 2x + 1.. but how do you do it like when theres no slope .... like that...

OpenStudy (anonymous):

ohhh I though 0 had to be on one side I guess it can be on the line too!

OpenStudy (anonymous):

Same thing :] Just graph whatever the graph would look like. In this case, the line would have no slope, or just be a vertical line at x=0. Then you shade the appropriate regions depending on whether it's greater than or less than

OpenStudy (anonymous):

Yup! :D I think you got it!

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

@DoubleCook one sec how do you know whether to shade the top or bottom part?

OpenStudy (anonymous):

You can plug in different values into your variable and check to see if it satisfies your inequality. If it does, then that "side" of the graph/line is usually shaded, but if not, try another value on the other side.

OpenStudy (anonymous):

I DONT GET IT I flutterING HATE MATH

OpenStudy (anonymous):

Ok, so first you want to graph the equation as if the inquality weren't there and it was just an equal sign. In this case, x=0. Then with the "greater than/less than" requirements, you plug in random x values on different sides of the line. So...you could try x=-1 and x=1. With the original inequality of x<0, see if it's true when you plug in the two values for x

OpenStudy (anonymous):

If it's true, shade it in, but if not, then don't

OpenStudy (anonymous):

@dpaInc

OpenStudy (anonymous):

@saifoo.khan

OpenStudy (anonymous):

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