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Okay so I have the answer to this, I just need to know how they got this answer. A certain species of dolphin breaths a mean of 2.31 times per minute with a variance of 1.28. Given the central limit theorem, if you repeatedly pull 17 dolphins from the population, what will be the variance of the mean of the sampling distribution?
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The answer is .08
I think all you have to do is divide by the sample size.
You can assume the population is large and normally distributed. \[σ_{\bar x}^2 = σ^2/n\] See http://stattrek.com/sampling/sampling-distribution.aspx
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