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log4096 (256)
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\(\huge log_{4096}(256) \) this the question?
yes
\[\log_{2^{12}}(2^8)\]
notice 4096 = 2^12 and 256 = 2^8
yes. and? sorry i forgot all my log rules
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writing this in exponential form: \(\large (2^{12})^x=2^8 \)
ahhh icic so -4?
no... what do you do to simplify power of a power??? for example, \(\large (3^2)^5=3^{???} \)
3^10
right... you multiply the exponents so the equation becomes: \(\large (2^{12})^x=2^{12x} \) \(\large 2^{12x}=2^8 \) 12x = 8
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icic ty so much
ok???? so x=2/3 ??? that what u got?
yw.,..:)
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