Suppose that the revenue generated by selling x units of a certain commodity is given by R = 1/5x^2 + 200x. Assume R is dollars. What is the maximum revenue possible in this situation?

Question

Suppose that the revenue generated by selling x units of a certain commodity is given by R = 1/5x^2 + 200x.  Assume R is dollars.  What is the maximum revenue possible in this situation?

anonymous · Answer

I got $150,000.00 - is that right?

anonymous · Answer

$$\frac{1}{5}x^2 + 200x$$
?

anonymous · Answer

yes

anonymous · Answer

i did x of the vertex and then the function of that to get the max value...

anonymous · Answer

there is no finite max to that equation

anonymous · Answer

it goes to infinity as x goes to infinity

anonymous · Answer

the minimum of that equation is at x = -500

anonymous · Answer

its value is about -50000

anonymous · Answer

im sorry its -1/5x^2

anonymous · Answer

ok

anonymous · Answer

and in that case im wrong... i gotta redo

anonymous · Answer

er no..

anonymous · Answer

you can just use the formula for the vertex of a quadratic:
$$\frac{-b}{2a}$$

anonymous · Answer

gives you an x coordinate of 500

anonymous · Answer

so 50k

anonymous · Answer

yes

anonymous · Answer

awesome.. u rock once again.  thanks so much

anonymous · Answer

You are welcome