Question

Suppose that the revenue generated by selling x units of a certain commodity is given by R = 1/5x^2 + 200x. Assume R is dollars. What is the maximum revenue possible in this situation?

Answer 1

I got $150,000.00 - is that right?

Answer 2

\[\frac{1}{5}x^2 + 200x\]
?

Answer 3

yes

Answer 4

i did x of the vertex and then the function of that to get the max value...

Answer 5

there is no finite max to that equation

Answer 6

it goes to infinity as x goes to infinity

Answer 7

the minimum of that equation is at x = -500

Answer 8

its value is about -50000

Answer 9

im sorry its -1/5x^2

Answer 10

ok

Answer 11

and in that case im wrong... i gotta redo

Answer 12

er no..

Answer 13

you can just use the formula for the vertex of a quadratic:
\[\frac{-b}{2a}\]

Answer 14

gives you an x coordinate of 500

Answer 15

so 50k

Answer 16

yes

Answer 17

awesome.. u rock once again. thanks so much

Answer 18

You are welcome