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Use a linear approximation (or differentials) to estimate the given number. (1.999)^4
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the formula for linear approximation is L(x)=f(a)+F'(a)(x-a) here try a=2 since its very close to 1.999 therefore L(x)=f(2)+F'(2)(x-2) since f(x)=x^4,f(2)=16,, f'(x)=4x^3, f'(2)=32 L(2)=16+32(2-2)=16 ANS
L(x)=16+32(x-2) l(X)=16+32X-64 l(X)=32X-48 AT X=2 L(2)=16 ...ans
Oh, I see. So you find L(x) using the formula and then plugging in 1.999 into x and a.
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