Can someone explain to me how to solve a quadratic equation?

Question

anonymous · Answer

Yep.

anonymous · Answer

I recommend starting in standard form, i.e.
 ax^2+bX+c=0
then either factor, complete the square, or use quadratic formula.

anonymous · Answer

Were you given any instructions on what method to use?

anonymous · Answer

The quadratic formula is what I think I used. It's been a while.

anonymous · Answer

Quadratic formula always works, but can sometimes be overkill if the quadratic is easily factored.

anonymous · Answer

Got an example you wanna run through?

anonymous · Answer

$$-b +/- \sqrt{b^2-4(a)(c)}$$ All that is over 2(a)

anonymous · Answer

Thanks!

anonymous · Answer

so for example if you're given the problem x^2+3x-4=0 you would do this.
-(3)+$$\sqrt{4(2)(-4)}$$ Then divide it by 2(1)

anonymous · Answer

Then you would do it where you minus rather than add after the -b part

anonymous · Answer

Ah

anonymous · Answer

So it's pretty much two problems, one where you add at the + or - square root part and one where you choose to minus.
I hope that's not confusing.

anonymous · Answer

Not really. Just a refresher.