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NEED HELP! A lunar lander, Apollo 10, is making its decent to Moon Base WPHS. The lander descends slowly under the retro-thrust of its descent engine. The engine is cut off when the lander is 5.0m above the surface and has a downward velocity of 0.8 m/s. With the engine off, the lander is in free fall what is the speed of the lander just before it touches the surface? The acceleration due to gravity on the moon is 1.6 m/s^2.
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Use: v^2=u^2 + 2as
u=0.8 m/s s=5.0m a=1.6m/s^2
Now, find v
I forgot to find v
v^2=(0.8)^2 + 2*1.6 *5
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Just simplify
I GOT 16.64 it looks wrong
That is right
yes
is that my final answer or I have to do more work
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Thats it
ok thanks for all your help
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