Question

Implicit differentiation: ycosx=x^2+y^2
what am i doing wrong here?
derivative of both sides:
=((y)(-sinx)+(cosx)(dy/dx)=2x+2y(dy/dx)

=(-ysinx+cosx(dy/dx)=2x+2y(dy/dx)

=cosx(dy/dx) - 2y(dy/dx) = ysinx+2x

=(cosx-2y)dy/dx = ysinx+2x

=dy/dx = (ysinx+2x)/(cosx-2y)

Answer 1

It looks right to me.

Answer 2

nick....honey.....dear.....any other form of weird name for reference......i have absolutely no clue what language this question is in

Answer 3

you just call me honey lol

Answer 4

is that really all you picked up from what i posted lol

Answer 5

Implicit differentiation: ycosx=x^2+y^2
((y)(-sinx)+(cosx)(dy/dx)=2x+2y(dy/dx)
(-ysinx+cosx(dy/dx)=2x+2y(dy/dx) collect terms
cosx(dy/dx)-2y(dy/dx)=2x+ysinx <----------
(dy/dx)(cosx-2y)=2x+ysinx
dy/dx))=(2x+ysinx)/(cosx-2y

Answer 6

seems like you did it correctly...lol :D

Answer 7

im starting to think my book might have some errors i appreciate mark and johnny

Answer 8

YW....ok maybe its the book since you done it right ..lol
have fun n good luck now