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CALCULATE mass of 2.2 x 10^20 Ag atom. the answer is 0.0432 g but i keep getting 0.0394 g. Somebody pls help explain this to me!
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2.2x10^20/6.023x10^23 then multiply by mass of Ag
I got 0.0394 as well
using ratio method, \[2.2 \times 10^{20} \text{Ag atom} \times \frac{1~mol}{6.02 \times 10^{23}atom} \times \frac{107.9g}{1mol}=0.039g~Ag\] Your answer is correct
thank you!
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