Question

List the members of the relation, R, if x is an integer, y=2x-1, and -3 <= x < 3

Answer 1

AP pre-cal is a pain in the behind lol

Answer 2

So here, like the last problem, you have the x values of [-3,-2,-1,0,1,2,3) Notice the square and round brackets too!
Plug it all into the y= equation and you have your y's :D

Answer 3

It's much like the previous question but "easier" in that you don't have to find the domain and range

Answer 4

And yeah, APs >.< meh haha Good college credit though :]

Answer 5

well, it said to find the domain and range on another question lol

Answer 6

and one question, on the previous question, you told me that i need to find the y values with the given list also?

Answer 7

like 3y=3-2x ; x E {0,2,4,6}...do i have to find the y values also?

Answer 8

Well it depends on what the question is asking...so for both, you'd have to find all the y-values...this question just asks for a list of them but the previous question asked you to take it a step further and find the domain and range, which isn't too difficult once you get the list of y-values

Answer 9

[-3,-2,-1,0,1,2,3) thats the list for the question i just asked?

Answer 10

These are the x- values, yup. But now you need to plug in each entry in place of the "x" in the equation of y=2x-1 so you get a list of the y-variables

Answer 11

ooooh

Answer 12

your a f'ing genius, you know that

Answer 13

all right can i ask you another question here or on a different question?

Answer 14

it also asks you for -3 <= x <3

Answer 15

all right nameless, do your magic

Answer 16

Haha thanks man :D
and sure thing!

Answer 17

Oh and the -3<= x <3 is there just to telll you which integers you use to plug into the equation y=2x-1

Answer 18

Because otherwise..there'd be infinite possibilities which is...undesirable

Answer 19

ooh all right, that makes it clear

Answer 20

all right so, last problem for tonight

Answer 21

x-3/5 over 2+3/x

Answer 22

\[x-3/5 \over 2+3/x\]

Answer 23

Ok and you're trying to simplify? Solve for x?

Answer 24

divide; simplify the results

Answer 25

divide; simplify the results

Answer 26

lagggg

Answer 27

you get that one?

Answer 28

Well...yes? It looks a bit more complex but if you're trying to get rid of the fractions on the top and bottom, then I think I got it

Answer 29

it's very complex lol

Answer 30

So take the numerator and denominator apart to get x-(3/5) on top...Then multiply x by 5 to get (5x-3)/5

Answer 31

Since 5x/5 is still x, you can combine them

Answer 32

So then you do the same to the denominator to get (2x+3)/x

Answer 33

a bit troubled

Answer 34

Now you have to separate, but whole fractions that you're dividing
The rule with dividing two fractions is that it's the same as multiplying the fraction in the numerator by the inverse of the denominator

Answer 35

so i seperate the numerator and denominator?