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Mathematics 8 Online
OpenStudy (anonymous):

Simplify (2x)^1/2 (2x)^1/3

OpenStudy (lgbasallote):

here's a hint... apply laws of exponents \[\huge a^m \times a^n \implies a^{m+n}\] does that help?

OpenStudy (anonymous):

2x^(1/6)?

OpenStudy (lgbasallote):

close.. very close... but 1/2 + 1/3 is not 1/6 try again

OpenStudy (anonymous):

I thought I was supposed to multiply...

OpenStudy (lgbasallote):

nope. like i wrote above, you just add the exponents

OpenStudy (anonymous):

ok, so 2x^(1/5)

OpenStudy (lgbasallote):

you multiply when it's like this \[\huge (a^m)^n \implies a^{mn}\] and 1/2 + 1/3 is still not 1/5

OpenStudy (anonymous):

5/6

OpenStudy (lgbasallote):

right.

OpenStudy (lgbasallote):

so now just put in 2x as the base

OpenStudy (anonymous):

2x^5/6

OpenStudy (lgbasallote):

nope. remember. there was a parenthesis in the original problem

OpenStudy (lgbasallote):

that parenthesis is very important

OpenStudy (anonymous):

why?

OpenStudy (lgbasallote):

because.. \\large [(2x)^{5/6} \implies 2^{5/6} x^{5/6}\]do you see the difference of that to 2x^5/6 ?

OpenStudy (lgbasallote):

\[\large [(2x)^{5/6} \implies 2^{5/6} x^{5/6}\]

OpenStudy (anonymous):

ok...

OpenStudy (lgbasallote):

so you got it now?

OpenStudy (anonymous):

yep :) thanks

OpenStudy (lgbasallote):

welcome

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