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Simplify (2x)^1/2 (2x)^1/3
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here's a hint... apply laws of exponents \[\huge a^m \times a^n \implies a^{m+n}\] does that help?
2x^(1/6)?
close.. very close... but 1/2 + 1/3 is not 1/6 try again
I thought I was supposed to multiply...
nope. like i wrote above, you just add the exponents
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ok, so 2x^(1/5)
you multiply when it's like this \[\huge (a^m)^n \implies a^{mn}\] and 1/2 + 1/3 is still not 1/5
5/6
right.
so now just put in 2x as the base
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2x^5/6
nope. remember. there was a parenthesis in the original problem
that parenthesis is very important
why?
because.. \\large [(2x)^{5/6} \implies 2^{5/6} x^{5/6}\]do you see the difference of that to 2x^5/6 ?
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\[\large [(2x)^{5/6} \implies 2^{5/6} x^{5/6}\]
ok...
so you got it now?
yep :) thanks
welcome
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