Mathematics
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OpenStudy (anonymous):
I don't know how to solve limits with square roots =_= ..
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OpenStudy (anonymous):
\[\lim_{x \rightarrow 1} \frac{ x - 1 }{ \sqrt{x} - 1 }\]
like this question maybe :l
OpenStudy (anonymous):
multiply denominator and numerator by [sqrt(x) + 1]
hartnn (hartnn):
ok, here try to rationalize the denominator, u know how ?
OpenStudy (anonymous):
no idea >_ <
hartnn (hartnn):
know the formula (a+b)(a-b) = ?
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OpenStudy (anonymous):
u mean the conjugate ?
hartnn (hartnn):
yup, conjugate of \(\sqrt x\)-1 is \(\sqrt x\)+1
OpenStudy (anonymous):
oh okie thanks .. i will solve it and i will give my final answer .. and i want to u check it if its right or wrong k ? :]
hartnn (hartnn):
sure
OpenStudy (anonymous):
:] k wait plz
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OpenStudy (anonymous):
the denominator will be \[(\sqrt{x} - 1)^{2}\]
OpenStudy (anonymous):
??
hartnn (hartnn):
nopes
OpenStudy (anonymous):
=.= what then ?
OpenStudy (anonymous):
+
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hartnn (hartnn):
u multiplied with \(\sqrt x\)+1 , right ?
so what is
( \(\sqrt x\)-1)( \(\sqrt x\)+1) = ?
use \((a+b)(a-b) = a^2-b^2\)
OpenStudy (anonymous):
for the denominator it will be \[(\sqrt{x}- 1)^{2}\] =_= .. and i know it
hartnn (hartnn):
how can u be so sure ?
OpenStudy (anonymous):
cuz i just solved it >_ > not the whole question .. a half of it
hartnn (hartnn):
\((\sqrt x-1)(\sqrt x-1)=(\sqrt x-1)^2 \\ \huge (\sqrt x-1)(\sqrt x+1)=((\sqrt x)^2-1^2)=?\)
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OpenStudy (anonymous):
the final answer is 2 .. am i right ?
OpenStudy (anonymous):
yes that what i just did (=_=)
hartnn (hartnn):
yes, final answer = 2 is correct!
OpenStudy (anonymous):
:]
OpenStudy (anonymous):
^_^ thanks for the HelP :3
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hartnn (hartnn):
welcome ^_^
OpenStudy (anonymous):
X3
But what if i got another question >_ > .. will u help mE :l
hartnn (hartnn):
you think, i'll help u ?
OpenStudy (anonymous):
cuz i got another question -..-' omg .. im sorry i feel like im using ur brain <_<'
OpenStudy (anonymous):
yeah Cuz ur SmaRt X]
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hartnn (hartnn):
whats the question ?
OpenStudy (anonymous):
Compute \[f ^{(45)} (x) for f(x)= e ^{2x} \] ?
hartnn (hartnn):
just a sec
OpenStudy (anonymous):
okie .. i think i got the idea but im not sure about it
OpenStudy (anonymous):
naahh . its wrong .. I don't know how to solve these kind of questions [ ̄Д ̄]
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hartnn (hartnn):
could you find f(1)(x) ?
OpenStudy (anonymous):
its 7.389
OpenStudy (anonymous):
?
hartnn (hartnn):
how could u get a number ?
hartnn (hartnn):
i was asking to differentiate f(x) once
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OpenStudy (anonymous):
i used the calculator >_ > .. from where u got F(1) ?
hartnn (hartnn):
to get \(f^{(1)}(x)\)
OpenStudy (anonymous):
-..- omg i feel dump
hartnn (hartnn):
\(f^{1}(x)= d/dx (e^{2x})=?\)
OpenStudy (anonymous):
how to do that =o= ?
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OpenStudy (anonymous):
ohh okie wait
OpenStudy (anonymous):
its 2 \[f \prime (x) = 2 e ^{2x}\]
OpenStudy (anonymous):
right ?
hartnn (hartnn):
yes.
now what is f''(x) ?
OpenStudy (anonymous):
i don't know >_ >
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hartnn (hartnn):
differentiate f'(x) once
OpenStudy (anonymous):
this is HARD >_<
OpenStudy (anonymous):
O_O
hartnn (hartnn):
\(f''(x)=d/dx (f'(x))= d/dx(2e^{2x})=2d/dx(e^{2x}=??)\)
OpenStudy (anonymous):
\[4e ^{2x}\] ?
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hartnn (hartnn):
yes. thats corrrect!
hartnn (hartnn):
4 = 2^2 , right ?
OpenStudy (anonymous):
8D ohh im Smart :B
OpenStudy (anonymous):
yes X3
OpenStudy (anonymous):
then .. F"'(x) ? till 45 times O_0 ?
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hartnn (hartnn):
so, \(f^{(1)}(x)= 2^1e^{2x} \\f^{(2)}(x)= 2^2e^{2x} \)
did u see the pattern ?
OpenStudy (anonymous):
BtW i didn't go to School today XD cuz i didn't finish my homework :B
OpenStudy (anonymous):
_this HW - >_ > '
OpenStudy (anonymous):
every time it gets to the power 2 .. yes
hartnn (hartnn):
right!
\(f^{n}(x)= 2^ne^{2x}\)
now just put n=45
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OpenStudy (anonymous):
i think \[2^{n} \] won't be correct
hartnn (hartnn):
why?
OpenStudy (anonymous):
-..- okie in wrong forget it
hartnn (hartnn):
so what u get when u put n= 45 in that ?
OpenStudy (anonymous):
\[3.52 \times 10^{13} e ^{2x} ?\]
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hartnn (hartnn):
i think u should keep it as 2^45 only.....or even this is correct.....
OpenStudy (anonymous):
=.= im not so sure about this one .. i should as my teacher about it
hartnn (hartnn):
ok.
OpenStudy (anonymous):
:} but thanks anyway X3 .. u're the best in this website really .. u are helping cuz u care about us XD thaaaaaaaaaaaanx X3
hartnn (hartnn):
welcome ^_^
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OpenStudy (anonymous):
i gtg now X] .. break time :] See u :P
hartnn (hartnn):
cya , bye :)
hartnn (hartnn):
close this question, if you are done with it.....
OpenStudy (anonymous):
oh oKie >0< .. btw .. i came back ang i bought an ice-cream :P
OpenStudy (anonymous):
- question closed - ( ^^)人(^^ ) << thats me and u :P
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hartnn (hartnn):
I ALSO WANT AN ICECREAM !
OpenStudy (anonymous):
-..- Sowwie .. (º_º) i wish i can give up oNe :l
hartnn (hartnn):
i will buy and eat it here....
hartnn (hartnn):
if i don't get , i'll eat u
OpenStudy (anonymous):
(✖╭╮✖')
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OpenStudy (anonymous):
enjoy ur ice-cream (⌒∇⌒。)
and Don't eat me -_-
hartnn (hartnn):
lol! i was jk, how would i eat you over internet ? :P
OpenStudy (anonymous):
(;¬_¬)