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Mathematics 20 Online
OpenStudy (anonymous):

I don't know how to solve limits with square roots =_= ..

OpenStudy (anonymous):

\[\lim_{x \rightarrow 1} \frac{ x - 1 }{ \sqrt{x} - 1 }\] like this question maybe :l

OpenStudy (anonymous):

multiply denominator and numerator by [sqrt(x) + 1]

hartnn (hartnn):

ok, here try to rationalize the denominator, u know how ?

OpenStudy (anonymous):

no idea >_ <

hartnn (hartnn):

know the formula (a+b)(a-b) = ?

OpenStudy (anonymous):

u mean the conjugate ?

hartnn (hartnn):

yup, conjugate of \(\sqrt x\)-1 is \(\sqrt x\)+1

OpenStudy (anonymous):

oh okie thanks .. i will solve it and i will give my final answer .. and i want to u check it if its right or wrong k ? :]

hartnn (hartnn):

sure

OpenStudy (anonymous):

:] k wait plz

OpenStudy (anonymous):

the denominator will be \[(\sqrt{x} - 1)^{2}\]

OpenStudy (anonymous):

??

hartnn (hartnn):

nopes

OpenStudy (anonymous):

=.= what then ?

OpenStudy (anonymous):

+

hartnn (hartnn):

u multiplied with \(\sqrt x\)+1 , right ? so what is ( \(\sqrt x\)-1)( \(\sqrt x\)+1) = ? use \((a+b)(a-b) = a^2-b^2\)

OpenStudy (anonymous):

for the denominator it will be \[(\sqrt{x}- 1)^{2}\] =_= .. and i know it

hartnn (hartnn):

how can u be so sure ?

OpenStudy (anonymous):

cuz i just solved it >_ > not the whole question .. a half of it

hartnn (hartnn):

\((\sqrt x-1)(\sqrt x-1)=(\sqrt x-1)^2 \\ \huge (\sqrt x-1)(\sqrt x+1)=((\sqrt x)^2-1^2)=?\)

OpenStudy (anonymous):

the final answer is 2 .. am i right ?

OpenStudy (anonymous):

yes that what i just did (=_=)

hartnn (hartnn):

yes, final answer = 2 is correct!

OpenStudy (anonymous):

:]

OpenStudy (anonymous):

^_^ thanks for the HelP :3

hartnn (hartnn):

welcome ^_^

OpenStudy (anonymous):

X3 But what if i got another question >_ > .. will u help mE :l

hartnn (hartnn):

you think, i'll help u ?

OpenStudy (anonymous):

cuz i got another question -..-' omg .. im sorry i feel like im using ur brain <_<'

OpenStudy (anonymous):

yeah Cuz ur SmaRt X]

hartnn (hartnn):

whats the question ?

OpenStudy (anonymous):

Compute \[f ^{(45)} (x) for f(x)= e ^{2x} \] ?

hartnn (hartnn):

just a sec

OpenStudy (anonymous):

okie .. i think i got the idea but im not sure about it

OpenStudy (anonymous):

naahh . its wrong .. I don't know how to solve these kind of questions [ ̄Д ̄]

hartnn (hartnn):

could you find f(1)(x) ?

OpenStudy (anonymous):

its 7.389

OpenStudy (anonymous):

?

hartnn (hartnn):

how could u get a number ?

hartnn (hartnn):

i was asking to differentiate f(x) once

OpenStudy (anonymous):

i used the calculator >_ > .. from where u got F(1) ?

hartnn (hartnn):

to get \(f^{(1)}(x)\)

OpenStudy (anonymous):

-..- omg i feel dump

hartnn (hartnn):

\(f^{1}(x)= d/dx (e^{2x})=?\)

OpenStudy (anonymous):

how to do that =o= ?

OpenStudy (anonymous):

ohh okie wait

OpenStudy (anonymous):

its 2 \[f \prime (x) = 2 e ^{2x}\]

OpenStudy (anonymous):

right ?

hartnn (hartnn):

yes. now what is f''(x) ?

OpenStudy (anonymous):

i don't know >_ >

hartnn (hartnn):

differentiate f'(x) once

OpenStudy (anonymous):

this is HARD >_<

OpenStudy (anonymous):

O_O

hartnn (hartnn):

\(f''(x)=d/dx (f'(x))= d/dx(2e^{2x})=2d/dx(e^{2x}=??)\)

OpenStudy (anonymous):

\[4e ^{2x}\] ?

hartnn (hartnn):

yes. thats corrrect!

hartnn (hartnn):

4 = 2^2 , right ?

OpenStudy (anonymous):

8D ohh im Smart :B

OpenStudy (anonymous):

yes X3

OpenStudy (anonymous):

then .. F"'(x) ? till 45 times O_0 ?

hartnn (hartnn):

so, \(f^{(1)}(x)= 2^1e^{2x} \\f^{(2)}(x)= 2^2e^{2x} \) did u see the pattern ?

OpenStudy (anonymous):

BtW i didn't go to School today XD cuz i didn't finish my homework :B

OpenStudy (anonymous):

_this HW - >_ > '

OpenStudy (anonymous):

every time it gets to the power 2 .. yes

hartnn (hartnn):

right! \(f^{n}(x)= 2^ne^{2x}\) now just put n=45

OpenStudy (anonymous):

i think \[2^{n} \] won't be correct

hartnn (hartnn):

why?

OpenStudy (anonymous):

-..- okie in wrong forget it

hartnn (hartnn):

so what u get when u put n= 45 in that ?

OpenStudy (anonymous):

\[3.52 \times 10^{13} e ^{2x} ?\]

hartnn (hartnn):

i think u should keep it as 2^45 only.....or even this is correct.....

OpenStudy (anonymous):

=.= im not so sure about this one .. i should as my teacher about it

hartnn (hartnn):

ok.

OpenStudy (anonymous):

:} but thanks anyway X3 .. u're the best in this website really .. u are helping cuz u care about us XD thaaaaaaaaaaaanx X3

hartnn (hartnn):

welcome ^_^

OpenStudy (anonymous):

i gtg now X] .. break time :] See u :P

hartnn (hartnn):

cya , bye :)

hartnn (hartnn):

close this question, if you are done with it.....

OpenStudy (anonymous):

oh oKie >0< .. btw .. i came back ang i bought an ice-cream :P

OpenStudy (anonymous):

- question closed - ( ^^)人(^^ ) << thats me and u :P

hartnn (hartnn):

I ALSO WANT AN ICECREAM !

OpenStudy (anonymous):

-..- Sowwie .. (º_º) i wish i can give up oNe :l

hartnn (hartnn):

i will buy and eat it here....

hartnn (hartnn):

if i don't get , i'll eat u

OpenStudy (anonymous):

(✖╭╮✖')

OpenStudy (anonymous):

enjoy ur ice-cream (⌒∇⌒。) and Don't eat me -_-

hartnn (hartnn):

lol! i was jk, how would i eat you over internet ? :P

OpenStudy (anonymous):

(;¬_¬)

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