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OpenStudy (anonymous):
Calculate the molarity of the solution.
29 g of NaCl (g.f.w. = 58.5 g/mol) in 0.030 liters.
0.015 M
17 M
67 M
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OpenStudy (anonymous):
First you want to find the moles of 29g of NaCl. Then you can plug it into the equation for molarity which is moles of solute/liter of solution.
OpenStudy (anonymous):
how do you do that???
OpenStudy (anonymous):
Find the moles of NaCl?
OpenStudy (anonymous):
How do you do that?!?
OpenStudy (anonymous):
29 g of Nacl * molar mass of NaCl= answer
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OpenStudy (anonymous):
I think she needs you to set it up in a equation
OpenStudy (anonymous):
I just did.
OpenStudy (anonymous):
Then you take that answer and put it over the liters of solution.
OpenStudy (anonymous):
this is my question.... how would you find the molar mass of NaCl?
OpenStudy (anonymous):
The molar mass is the sum of the atomic mass' of the Na+Cl
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OpenStudy (anonymous):
which is X grams/moles
OpenStudy (anonymous):
moles = given wt/mol. Wt
Mol.wt of nacl=23+35.5=58.5 gm
Moles = 29/58.5 = 0.495 = 0.5 moles (approx)
OpenStudy (anonymous):
ok... i got the molar mass as 58.442 so will i do 29 * 58.442
OpenStudy (anonymous):
@aussy123 you've got something a little wrong there hun
OpenStudy (anonymous):
Oh sorry I missed 0.015M
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