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solve : x − 8 = √(-18x + 67)
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start with \((x-8)^2=-18x+67\) solve the quadratic equation and don't forget to check your solution in the original equation
1 or -3
nope
x^2+64-16x=-18x+67 x^2+2x-3=0 (x-1)(x+3)=0
so there r 2 solutions
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hmmm really?
if you square both sides of an equation, you can introduce extraneous solutions we know \(-5\) is not a solution to \(x+1=4\) but if we square both sides, it is a solution to \((x+1)^2=16\) by squaring, we have introduces an additional solution, namely \(-5\) to the original equation \(x+1=4\)
that is why you have to check both solutions after you square, to see if they work. \(-3\) is not a solution to \[x-8=\sqrt{-18x+67}\]
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