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How do I find the inverse of this relation: y=3(2)^x???
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\[y=3*2^x\]
this is the question ?
yup!
ok divide both sides by 3 (y/3) = 2^x now introduce ln in both sides.. does it help?
This is what I've done so far: y=3(2)^x x = 3(2)^y x/3 = 2^y logx/3 = log2^y logx/3 = ylog2 log(x/3)/log2 = y Using change of base formula: log[2](x/3).... but it's not right :(
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the correct answer states, \[y = \sqrt[3]{2\div3}\]
i mean, \[y = \sqrt[3]{2}\div3 \]
it is the right answer .. something wrong with the answer that you say its correct
really?.. oh, okay. thank you!
yw
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