Question

how many different ways can 2 black, 3 blue, and 4 red marbles be arranged?

Answer 1

1*2*3*4*5*6*7*8*9

Answer 2

That should give you the answer
Just count how many total subjects involved. For this problem, 9. Then count up and multiply at the same time.

Answer 3

i have the answer: 1260. But I do not understand how to get it.

Answer 4

Like I said, just count the total number of subjects, this being 9 because 4+3+2 =9
Just multiply

Answer 5

Does that answer your question? :)

Answer 6

but 9! does not equal 1260

Answer 7

Yes, I know
You multiplied 1*2*3*4*5*6*7*8*9

Answer 8

ok, so how do I solve again?

Answer 9

if you could tell the marbles apart, it would be 9! but since you cannot tell the colors apart (i am assuming) it is
\[\frac{9!}{2!3!4!}\]

Answer 10

Count exactly how many total subjects (in this case marbles) , 9 because 4+3+2=9. Then count from 1 up to 9, so 123456789, then insert multiplication signs in between each number, so 1*2*3*4*5*6*7*8*9... If I'm not mistaken

Answer 11

You can tell them apart, can't you, hence the color coding?

Answer 12

divide by by the number of ways you can arrange the 2 black,3 red and 4 blue because you cannot tell them apart

Answer 13

you cannot tell red from red though

Answer 14

ah. I see.

Answer 15

Well we all learned something today! :) Thank you

Answer 16

I tried 9!/2!3!4! and I got 630

Answer 17

I have here the answer should be 120

Answer 18

That seems more accurate.

Answer 19

I'm sorry, I have that the answer should be 1260

Answer 20

I tried 9!/2!3!4! and I got 630

Answer 21

the answer should be 1260