A girl coasts down a hill on a sled, reaching
a level surface at the bottom with a speed
of 7.6 m/s. The coeﬃcient of kinetic friction
between runners and snow is 0.052, and the
girl and sled together weigh 744 N.
The acceleration of gravity is 9.8 m/s
2
.
How far does the sled travel on the level
surface before coming to a rest?
Answer in units of m

Question

A girl coasts down a hill on a sled, reaching
a level surface at the bottom with a speed
of 7.6 m/s. The coeﬃcient of kinetic friction
between runners and snow is 0.052, and the
girl and sled together weigh 744 N.
The acceleration of gravity is 9.8 m/s
2
.
How far does the sled travel on the level
surface before coming to a rest?
Answer in units of m

anonymous · Answer

Ff = .052*744N

a= Ff/m = Ff/(744N/g) 

a = .052g

use in:

Vf^2 = 0 =  Vi^2 -2*a*d

to find d