Determine the constant k so that the graph of 3(y-3k) = 2k(x+1) will have a slope of 4.

Question

anonymous · Answer

2k(x+1) should be 2kx + 2k not 2kx +2 right?

anonymous · Answer

yes, sorry... I read it wrong.

anonymous · Answer

first, simplify by multiplying the expressions out...

3(y - 3k) = 2k(x + 1)
3y - 9k = 2kx + 2k

anonymous · Answer

3y = 2kx + 2k + 9k
3y = 2kx + 11k
y = (2k/3)x + (11k/3)

So the slope is the coefficient of the x term, (2k/3)

And you need to find k so that the slope (2k/3) is equal to 4

anonymous · Answer

So that leaves k=6?

anonymous · Answer

that's what it looks like to me :)

anonymous · Answer

Thanks! I knew I had to get it k as the slope = 4 but wasn't sure exactly how. :D

anonymous · Answer

glad to help... 

you just needed to move terms around in the original equation until you have it in a form like "y  =  mx  +  b"

Good job :)

anonymous · Answer

Makes sense!