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OpenStudy (anonymous):

How many grams of NH3 are needed to provide the same number of molecules as in 0.65 grams of SF6?

OpenStudy (anonymous):

@saifoo.khan @dpaInc Help please!

OpenStudy (anonymous):

@cwrw238

OpenStudy (anonymous):

@robtobey

OpenStudy (anonymous):

@TuringTest

OpenStudy (anonymous):

@TuringTest @shadowfiend @ganeshie8

OpenStudy (anonymous):

@zbay @AccessDenied @JakeV8

OpenStudy (anonymous):

Fine the molar mass for each of the compounds and I will help you out a little bit

OpenStudy (anonymous):

\[.65g SF_6 (\frac{1 mole SF_6}{ molar mass SF_6 })(\frac{ molar mass NH_3}{1 mole NH_3})=\]

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