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OpenStudy (anonymous):
How many grams of NH3 are needed to provide the same number of molecules as in 0.65 grams of SF6?
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OpenStudy (anonymous):
@saifoo.khan @dpaInc Help please!
OpenStudy (anonymous):
@cwrw238
OpenStudy (anonymous):
@robtobey
OpenStudy (anonymous):
@TuringTest
OpenStudy (anonymous):
@TuringTest @shadowfiend @ganeshie8
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OpenStudy (anonymous):
@zbay @AccessDenied @JakeV8
OpenStudy (anonymous):
Fine the molar mass for each of the compounds and I will help you out a little bit
OpenStudy (anonymous):
\[.65g SF_6 (\frac{1 mole SF_6}{ molar mass SF_6 })(\frac{ molar mass NH_3}{1 mole NH_3})=\]
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