suppose xy=3 and dy/dt=4. find dx/dt when x=-2
I got 16/3
(dy/dt)/(dx/dt)=dy/dx Solve for y when x =-2 for starters then find dy/dx implicitly.
I don't know how to do that? :/
Can you tell me how like generally so i can solve it?/
Starting by solving for y?
doesn't y=3?
xy=y?
when x=2?\[xy=3\]\[-2y=3\]
-3/2
yes. Now you have an ordered pair (-2, -3/2) which will come in handy later.
Can you differentiate implicitly?
No, that's what I don't understand at all.
Well, you could say that all differentiation is implicit, because when we differentiate implicitly we treat the y as a variable to be differentiated, with all the usual rules in effect. \[\frac{ d }{ dx }(y)=\frac{ dy }{ dx }\] What we'll do, though instead of using the product rule on xy, is solve for y and differentiate. That should be easier. So,\[xy=3\]\[y=\frac{ 3 }{ x }\]Can you differentiate that?
You could also write the x with a negative exponent if you prefer the power rule
-3/x^2?
Yeah. When you substitute x=-2, you get the slope, or dy/dx, which I said earlier was equal to (dy/dt)/(dx/dt)
3/4
negative
4=3/4*dx/dt?
oh -3/4
otherwise you're right. Just solve.
19/4
You dropped the negative sign, and where did you get 19??
4+3/4?
my calculator gave me 19/4
You weren't supposed to add. 4=dy/dt. -3/4=dy/dx. dy/dx=(dy/dt)/(dx/dt). dx/dt=?
-16/3, I got it...
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