Given that "f" is an ODD function and f(x+5)=f(x), f(1/3)=1. Find the value of f(14/3)
If f is odd, then f(-x)=-f(x), but I'm actually not sure how to advance here. Anyone have any ideas?
Does it assume the function is linear?
I think--and here I may be going out on a limb--that this problem excludes important info.
f(x+5)=f(x) f(-x+5)=-f(x) 14/3=-1/3+5 that is all you need to solve this
@auora could you interact with us here please?
does giving me a medal mean that you got it?
To be honest, @TuringTest, I don't understand. Your second step lost me. I understand the rest now; common sense, although I missed it.
you want me to give show you then you mean?
Yes.
\[f(x+5)=f(x)\]\[f(\frac13)=1\]since f(x) is odd we can write\[f(-x+5)=f(-x)=-f(x)\]now since \(\frac{14}3=-\frac13+5\) we can write\[f(\frac{14}3)=f(-\frac13+5)=f(-\frac13)=-f(\frac13)=-1\]
I would have distribute the negative onto both terms of x+5. Why didn't you?
distributed
You can't really do that. There is no reason to think that -x=-(x+5), so making one argument negative does not make the other whole argument negative, just x. We also have no reason to thin that f(x+5) is odd. The only thing we can do is let x=-x, changing nothing else, from which the above follows.
think*
let x=-y if you wish would that imply that f(x+5)=f(x) leads to f(-y-5)=f(-y) no, it leads to f(-y+5)=f(-y)
All, I think I understand now. Thanks for your help.
Anytime :)
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