Question

Write an equation of a line that is parallel and perpendicular to the above equation.

Answer 1

a) \[y=\frac{ 2 }{ 3 }x + \frac{ 4 }{ 3 }\]

Answer 2

do you have a point that the lines must go through?

Answer 3

Yeah, given points: (-2,-3) (4,1) I honestly don't know how to do this...I have to do this for 2 more problems.

Answer 4

Given the points (-2,-3) (4,1)
Write the equation in:
a)Point slope form - y+3=\[\frac{ 2 }{ 3 }(x+2)

Answer 5

(-2,-3) for parallel and (4,1)for perpendicular?

Answer 6

i'm not sure...my teacher just gave me these 2 points.

Answer 7

Hmm... You usually can't do these types of problems without knowing that. do you just want to assume that(-2,-3) is for parallel and (4,1) is for perpendicular?

Answer 8

is this for a geometry class?

Answer 9

nope. It's algebra... D:

Answer 10

Sure...i'll assume that.

Answer 11

oh okay. i'm doing this in geometry XD

Answer 12

,I like dk how to do this...for a. I got y=2/3x+5/3 for parallel and y=3/2x for perpendicular. But wouldn't it be that b and c is the same thing?

Answer 13

... anybody know how to do it?

Answer 14

so for parallel lines, the slope stays the same. so a line parallel to
y=2/3x+4/3 would have a slope of 2/3.

also, if it went through point (-2,-3), you would do this:
y=2/3x+b
-3=2/3(-2)+b
-3=-4/3+b
-13/3=b
-4 and 1/3=b

so the equation would be y=2/3x-4u1/3

it has to be in point slope form, though. WAIT a sec, is this the same?
Given the points (-2,-3) (4,1) Write the equation in: a)Point slope form - y+3=\[\frac{ 2 }{ 3 }(x+2). What is y+3=\[\frac{ 2 }{ 3 }(x+2)

Answer 15

can you put that in an equation format please?

Answer 16

i'm sorry, im a little bit confused. you still there?

Answer 17

yes.

Answer 18

I'm trying to work it out also. x3

Answer 19

okay . what is this?
y+3=\[\frac{ 2 }{ 3 }(x+2)

Answer 20

\[y+3=\frac{ 2 }{ 3 }(x+2)\]

Answer 21

like can you make it readable?

Answer 22

what'do you mean by readable? x3

Answer 23

you already did it jk :)

Answer 24

oh okay. :3

Answer 25

so is the problem y=2/3x+4/3 like you said in the first post, or y+3=2/3(x+2)?

Answer 26

y=2/3x+5/3... was the answer for parallel..the other one was the equation...

Answer 27

And for perpendicular, it's y=3/2x...

Answer 28

um...here
a)y+3=2/3(x+2)
b)y=2/3x-5/3
c)2x-3y=5

Answer 29

...

Answer 30

sorry working on it.

Answer 31

mk... x3

Answer 32

Thanks a lot btw.. :)

Answer 33

this is a. i m really sorry, i have a load of homework myself. I'll keep this page up in case you need help on B and C, but ive gotta work on mine too XD and you're welcome!