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Find the limit as delta(x) approaches 0, f(x)=[sin[(pi/6)+delta(x)]-(1/2)]/delta(x)
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use\[\sin(\alpha+\beta)=\sin\alpha\cos\beta+\cos\alpha\sin\beta\]
[(sin pi/6)(cos delta x)+(cos pi/6)(sin delta x)-(1/2)]/ delta x
[(1/2)(cos delta x)+(sqrt{3}\2)(sin delta x)-(1/2)]/ delta x
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sqrt{3}/2
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