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Determine f′(x) for f(x)=(ln(3x))^9.
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Have you learned derivatives of logarithmic functions?
yea dont we use chain rule?
ln u = u'/u
If\[y =c [\ln f(x)]^{n}\]then\[\frac{ dy }{ dx }=cn[\ln f(x)]^{n -1}\frac{ f \prime(x) }{ f(x) }\]because\[\frac{ d(\ln f(x)) }{ dx }=\frac{ f \prime(x) }{ f(x) }\]Note that in the above c is a constant. Does this help?
i dont get it :C
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soo 9(ln(3x))^8(3/3x)
Yeah.
ohhh ok ty.
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